handslive: (Default)
handslive ([personal profile] handslive) wrote2006-01-30 06:39 am
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The Golden Spruce - John Vaillant

Finished it on Friday.  No other comments.  The first rule of book club is we don't talk about book club. :-)
buhrger: (Default)

[personal profile] buhrger 2006-01-30 07:20 pm (UTC)(link)
meanwhile, any progress with the group theory?

[identity profile] handslive.livejournal.com 2006-01-30 11:31 pm (UTC)(link)
I've read the introduction as you indicated; skipped the "Application of Dihedral Groups" chapter altogether; skimmed chapter 3 "Groups"; felt a strong urge to do the example problem sets because my brain kept saying, "oh, yes, I remember that" but I wonder if I really do.

I should return it, then, yes?
buhrger: (Default)

[personal profile] buhrger 2006-01-30 11:47 pm (UTC)(link)
if you're not planning on going back to it in the next few months, you could probably return it, but there's no real hurry on this end. i was more curious to hear how it was going.
in related news, i'm into chapter 6 or 7 of your crypto book - it's my in-classroom reading for when students are working on assignments.

[identity profile] handslive.livejournal.com 2006-01-31 05:46 pm (UTC)(link)
Not completely on topic, but...

The definition given for modular arithmetic (pg 7) uses the "remainder" definition I learned in high school. My memory of this definition from university is that it's actually the set of all numbers in the set of (positive?) Integers with the property that they return this remainder. The idea being that:

3 mod 7 => (3, 10, 17, 24, ...)

But we usually represent the number as '3' for simplicity. Am I out to lunch? It's been a long time.
buhrger: (Default)

[personal profile] buhrger 2006-01-31 06:11 pm (UTC)(link)
the two definitions are equivalent. the official mathematical machinery is as follows:
we define an equivalence ~ by a ~ b if a-b is a multiple of seven. then the sets of which you speak are the equivalence classes of Z with respect to ~. it's fairly easy to show that each of those equivalence classes has precicsely one representative in the integers 0, 1, 2, 3, 4, 5, 6, and slightly more fiddly, but not too complicated to show that we can get away with just doing our arithmetic on those representatives.